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Answer by Paul Sanders for Can a write to std::atomic go unseen by other...
So, to provide a definitive answer to this, no, a write from thread1 will never be missed by thread0.This is because std::atomic::compare_exchange_strong is an atomic operation so the write from...
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std::atomic<int> g_atomic;void thread0(){ int oldVal = 0; int newVal = 1; while (g_atomic.compare_exchange_strong(oldVal, newVal, std::memory_order_acq_rel, std::memory_order_acquire)) { //...
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